Don’t you take the derivative first to get velocity as a fuction of time?
h'(t) =40-10t =v(t)
and so by your method that woud yield:
Vave = v(5)-v(0)/5 = -10m/s
The final answer is:
Determine the average velocity of the ball
During the first 5 seconds.
Average rate of change= f(b)- f(a)/ b- a
Average velocity
Vave= h(5)-h(0)/5-0
[40(5)-5(5)2] – [40(0)-5(0)2]/5
= 200- 125/5
=75/5
=15m.s-1
iPractice Math 
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Very Good!
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how do you work it out without calculating the velocity at every second?
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During the first 5 seconds.
Average rate of change= f(b)- f(a)/ b- a
Average velocity
Vave= h(5)-h(0)/5-0
LikeLike
Don’t you take the derivative first to get velocity as a fuction of time?
h'(t) =40-10t =v(t)
and so by your method that woud yield:
Vave = v(5)-v(0)/5 = -10m/s
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The final answer is:
Determine the average velocity of the ball
During the first 5 seconds.
Average rate of change= f(b)- f(a)/ b- a
Average velocity
Vave= h(5)-h(0)/5-0
[40(5)-5(5)2] – [40(0)-5(0)2]/5
= 200- 125/5
=75/5
=15m.s-1
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