Don’t you take the derivative first to get velocity as a fuction of time?
h'(t) =40-10t =v(t)
and so by your method that woud yield:
Vave = v(5)-v(0)/5 = -10m/s

The final answer is:
Determine the average velocity of the ball
During the first 5 seconds.
Average rate of change= f(b)- f(a)/ b- a
Average velocity
Vave= h(5)-h(0)/5-0
[40(5)-5(5)2] – [40(0)-5(0)2]/5
= 200- 125/5
=75/5
=15m.s-1

15

LikeLike

Very Good!

LikeLike

how do you work it out without calculating the velocity at every second?

LikeLike

During the first 5 seconds.

Average rate of change= f(b)- f(a)/ b- a

Average velocity

Vave= h(5)-h(0)/5-0

LikeLike

Don’t you take the derivative first to get velocity as a fuction of time?

h'(t) =40-10t =v(t)

and so by your method that woud yield:

Vave = v(5)-v(0)/5 = -10m/s

LikeLike

The final answer is:

Determine the average velocity of the ball

During the first 5 seconds.

Average rate of change= f(b)- f(a)/ b- a

Average velocity

Vave= h(5)-h(0)/5-0

[40(5)-5(5)2] – [40(0)-5(0)2]/5

= 200- 125/5

=75/5

=15m.s-1

LikeLike